Compare version numbers

Link: https://leetcode.com/problems/compare-version-numbers/

Solution:

Topics: two pointer

Intuition
Pretty trivial problem. One thing to note: int(x) in python removes leading zeros, so its the perfect function for this problem.

Implementation

def version_nums(version1, version2):
	v1 = version1.split('.')
	v2 = version2.split('.')
	
	for i in range(max(len(v1), len(v2))):
		first = int(v1[i]) if i < len(v1) else 0
		second = int(v2[i]) if i < len(v2) else 0
		if first < second:
			return -1
		if first > second:
			return 1
	return 0
 
#time: o(n)
#memory: o(n)

Review 1
Cute little problem! Clean implementation is not obvious, so it’s a good one.

review